2x^2+35x+153=0

Solution for 2x^2+35x+153=0 equation:

2x^2+35x+153=0

a = 2; b = 35; c = +153;
Δ = b2-4ac
Δ = 352-4·2·153
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-1}{2*2}=\frac{-36}{4}
=-9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+1}{2*2}=\frac{-34}{4}
=-8+1/2
$